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在Oracle中实现各种日期处理完全版
来源:设计前沿收集   作者:未知   更新时间:2009-02-04
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TO_DATE格式
  Day:   
  dd    number     12
  dy    abbreviated  fri     
  day   spelled out  friday            
  ddspth  spelled out,  ordinal  twelfth
  Month:  
  mm    number     03
  mon   abbreviated  mar
  month  spelled out  march 
  Year:             
  yy    two digits  98
  yyyy   four digits  1998  
  
  24小时格式下时间范围为: 0:00:00 - 23:59:59....
  12小时格式下时间范围为: 1:00:00 - 12:59:59 ....  
1.
  日期和字符转换函数用法(to_date,to_char)   
 
2.
  select to_char( to_date(222,'J'),'Jsp') from dual
  
  显示Two Hundred Twenty-Two
 
3.
  求某天是星期几
  select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day') from dual; 
  星期一
  select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE = American') from dual; 
  monday  
  设置日期语言
  ALTER SESSION SET NLS_DATE_LANGUAGE='AMERICAN';
  也可以这样
  TO_DATE ('2002-08-26', 'YYYY-mm-dd', 'NLS_DATE_LANGUAGE = American')
 
4.
  两个日期间的天数
  select floor(sysdate - to_date('20020405','yyyymmdd')) from dual;
 
5.   时间为null的用法
  select id, active_date from table1
   UNION
  select 1, TO_DATE(null) from dual;
  
  注意要用TO_DATE(null)
 
6. 
  a_date between to_date('20011201','yyyymmdd') and to_date('20011231','yyyymmdd')
  那么12月31号中午12点之后和12月1号的12点之前是不包含在这个范围之内的。
  所以,当时间需要精确的时候,觉得to_char还是必要的
7.   日期格式冲突问题
     输入的格式要看你安装的ORACLE字符集的类型, 比如: US7ASCII, date格式的类型就是: '01-Jan-01'
  alter system set NLS_DATE_LANGUAGE = American
     alter session set NLS_DATE_LANGUAGE = American
  或者在to_date中写
  select to_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE = American') from dual; 
  注意我这只是举了NLS_DATE_LANGUAGE,当然还有很多,
  可查看
  select * from nls_session_parameters
  select * from V$NLS_PARAMETERS
 

 日期和字符转换函数用法(to_date,to_char)
     We overwrite NLS_DATE_FORMAT into different formats for the session. 
     SQL> alter session set nls_date_format = 'DD-MON-RR'; Session altered.
     SQL> set pagesize 0
   SQL> set linesize 130
   SQL> select * from nls_session_parameters;
   NLS_LANGUAGE          AMERICAN
   NLS_TERRITORY         AMERICA
   NLS_CURRENCY          $
   NLS_ISO_CURRENCY        AMERICA
   NLS_NUMERIC_CHARACTERS     .,
   NLS_CALENDAR          GREGORIAN
   NLS_DATE_FORMAT        DD-MON-RR
   NLS_DATE_LANGUAGE       AMERICAN
   NLS_SORT            BINARY
   NLS_TIME_FORMAT        HH.MI.SSXFF AM
   NLS_TIMESTAMP_FORMAT      DD-MON-RR HH.MI.SSXFF AM
   NLS_TIME_TZ_FORMAT       HH.MI.SSXFF AM TZH:TZM
   NLS_TIMESTAMP_TZ_FORMAT    DD-MON-RR HH.MI.SSXFF AM TZH:TZM
   NLS_DUAL_CURRENCY       $
   NLS_COMP            BINARY

   15 rows selected.
     specify it in SQL statement:
     
    SQL> select to_date('03-SEP-1999','DD-MON-YYYY') from dual;
     03-SEP-99
    SQL> alter session set nls_date_format = 'MM-DD-YYYY';
       Session altered.
      
    SQL> select to_date('03-SEP-99','DD-MON-YY') from dual;
       TO_DATE('0
       ----------
       09-03-1999 
    SQL> alter session set nls_date_format = 'RRRR-MM-DD';
       Session altered. 
      
    SQL> select to_date('03-SEP-1999','DD-MON-YYYY') from dual;
       TO_DATE('0
       ----------
       1999-09-03 
      
  When we use TO_CHAR function, we get expected results of format from current SQL statement: 
    SQL> alter session set nls_date_format = 'MM-DD-YY';
       Session altered. 
    SQL> select to_char(sysdate,'dd-mm-yyyy') from dual;
       TO_CHAR(SYSDATE,'DD-MM-YYYY') 
       07-09-1999 
    SQL> alter session set nls_date_format = 'RR-MON-DD';
       Session altered. 
    SQL> select to_char(sysdate,'dd-mon-yy') from dual;
       TO_CHAR(SYSDATE,'DD-MON-YY') 
       07-sep-99 
    SQL> select to_char(sysdate,'dd-Mon-yy') from dual;
       TO_CHAR(SYSDATE,'DD-MON-YY') 
       07-Sep-99
8.
  select count(*) 
  from ( select rownum-1 rnum 
     from all_objects 
     where rownum <= to_date('2002-02-28','yyyy-mm-dd') - to_date('2002-
     02-01','yyyy-mm-dd')+1 
     ) 
  where to_char( to_date('2002-02-01','yyyy-mm-dd')+rnum-1, 'D' )
  not 
  in ( '1', '7' )
  
  查找2002-02-28至2002-02-01间除星期一和七的天数
  在前后分别调用DBMS_UTILITY.GET_TIME, 让后将结果相减(得到的是1/100秒, 而不是毫秒).  
 
9.
  select months_between(to_date('01-31-1999','MM-DD-YYYY'), 
   to_date('12-31-1998','MM-DD-YYYY')) "MONTHS" FROM DUAL; 
  1
  
  select months_between(to_date('02-01-1999','MM-DD-YYYY'),  
   to_date('12-31-1998','MM-DD-YYYY')) "MONTHS" FROM DUAL; 
  
  1.03225806451613
10.   Next_day的用法
  Next_day(date, day)
  
  Monday-Sunday, for format code DAY   
  Mon-Sun, for format code DY     
  1-7, for format code D 
 
11   
  select to_char(sysdate,'hh:mi:ss') TIME from all_objects
  注意:第一条记录的TIME 与最后一行是一样的
  可以建立一个函数来处理这个问题
  create or replace function sys_date return date is 
  begin 
  return sysdate; 
  end; 
  
  select to_char(sys_date,'hh:mi:ss') from all_objects; 
12.
     获得小时数
     
     SELECT EXTRACT(HOUR FROM TIMESTAMP '2001-02-16 2:38:40') from offer
     SQL>  select sysdate ,to_char(sysdate,'hh') from dual;
     
     SYSDATE       TO_CHAR(SYSDATE,'HH')
     -------------------- ---------------------
     2003-10-13 19:35:21 07
     
     SQL>  select sysdate ,to_char(sysdate,'hh24') from dual;
     
     SYSDATE       TO_CHAR(SYSDATE,'HH24')
     -------------------- -----------------------
     2003-10-13 19:35:21 19
     
     获取年月日与此类似
13.
  年月日的处理
  select older_date,
      newer_date,
      years,
      months,
      abs(
       trunc(
         newer_date-
           add_months( older_date,years*12+months )
          )
       ) days
   from ( select 
     trunc(months_between( newer_date, older_date )/12) YEARS,
    mod(trunc(months_between( newer_date, older_date )), 
       12 ) MONTHS,
          newer_date,
          older_date
        from ( select hiredate older_date,
         add_months(hiredate,rownum)+rownum newer_date
            from emp )
      )
 
14.
  处理月份天数不定的办法
  select to_char(add_months(last_day(sysdate) +1, -2), 'yyyymmdd'),last_day(sysdate) from dual
 
16.
  找出今年的天数
  select add_months(trunc(sysdate,'year'), 12) - trunc(sysdate,'year') from dual
  
  闰年的处理方法
  to_char( last_day( to_date('02'
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